perf: remove double check for keywords in readWord

Instead of calling isKeyword we simple check directly if the keyword token is available

packages/babel-parser/src/plugins/flow.js

@@ -1190,9 +1190,6 @@ export default (superClass: Class<Parser>): Class<Parser> =>
         case "any":
           return this.finishNode(node, "AnyTypeAnnotation");
 
-        case "void":
-          return this.finishNode(node, "VoidTypeAnnotation");
-
         case "bool":
         case "boolean":
           return this.finishNode(node, "BooleanTypeAnnotation");
@@ -1369,6 +1366,10 @@ export default (superClass: Class<Parser>): Class<Parser> =>
             "NumberLiteralTypeAnnotation",
           );
 
+        case tt._void:
+          this.next();
+          return this.finishNode(node, "VoidTypeAnnotation");
+
         case tt._null:
           this.next();
           return this.finishNode(node, "NullLiteralTypeAnnotation");
@@ -1922,16 +1923,6 @@ export default (superClass: Class<Parser>): Class<Parser> =>
       }
     }
 
-    // don't consider `void` to be a keyword as then it'll use the void token type
-    // and set startExpr
-    isKeyword(name: string): boolean {
-      if (this.state.inType && name === "void") {
-        return false;
-      } else {
-        return super.isKeyword(name);
-      }
-    }
-
     // ensure that inside flow types, we bypass the jsx parser plugin
     getTokenFromCode(code: number): void {
       const next = this.state.input.charCodeAt(this.state.pos + 1);